下载 12 Beads (12 Tini/Sholo Guti/12 Daane) - v1.0.26

下载 12 Beads (12 Tini/Sholo Guti/12 Daane) - v1.0.26
Package Name com.barabead.harjinder.a12bead
Category ,
Latest Version 1.0.26
Get it On Google Play
Update June 28, 2020 (4 years ago)

游戏和Bingo Blitz™️ - Bingo Games, Chess Coach Pro Mod (Professional version) MOD APK, Talisman Mod (已解锁) MOD APK, ZingPlay Portal - Games Center - Tongits - Pusoy, Ludo Club - Fun Dice Game, Ubongo Puzzle Challenge Mod Full v1.4.0 MOD APK一样好,12 Beads (12 Tini/Sholo Guti/12 Daane) - v1.0.26也很多,是类型桌面和棋类中最出色的游戏之一。

由App's Shop开发,12 Beads (12 Tini/Sholo Guti/12 Daane) - v1.0.26至少需要Android版本Android 4.2+。因此,如有必要,您必须更新手机。

12 Beads (12 Tini/Sholo Guti/12 Daane) - v1.0.26 APK的最新版本为1.0.26,发行日期为2020-06-28,大小为5.6 MB。

有关1000下载的统计信息可从Google Play获得。您可以根据需要更新已单独下载或安装在Android设备上的应用。更新您的应用可以为您提供更多功能。您可以访问最新功能并提高安全性和应用程序的稳定性。

由于并非所有游戏或应用程序都兼容所有手机。并且游戏或应用程序不适用于您的设备,因此取决于Android OS版本,屏幕分辨率或Google Play允许访问的国家/地区。因此,通过APK4Share,您可以轻松下载APK文件,不受这些限制。

12 Beads (12 Tini/Sholo Guti/12 Daane) - v1.0.26

12 Beads (12 Tini/Sholo Guti/12 Daane) Game

In this game two player can participate. Both players will have 12 beads, which they have to save from opposite player. One player turn first and second player needs to wait till his/her turn. When both player register, game starts automatically. After that the first player must move his/her bead to nearest destination but, initially player need to choose his/her bead.

Players can move their bead in two ways, which are following.
1. By moving nearest bead.
2. By crossing another player's bead.

In first way players can save their bead from another player.

Note: Players can move bead to nearest place only once in their single turn.

In Second way players can cross another's player bead if nearest bead is opponent's bead and crossed location is empty, in other words there is no any bead in crossed point. After crossing bead, player need to pass turn by clicking on PASS button or by clicking on a bead which he/she moved after crossed

Note: Players can crossed more than one bead in their single turn.

Result will depend on which player will lose first his/her all 12 beads. For Instance: if player first will lose his/her bead than winner is player second."

Added Remove Ads FeatureFixed Bugs Improved Performance

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